I am trying to put together my first mod and wondering the reason for the resistor between the momentary switch and LED, I know it has one I just don't know. The plan is to use a 18650 type batt. momentary switch and a led. Also is there an advantage with using a pcb? Thanks for the help.
Because if you throw 3.7V of power at a 1.5V LED. It will blow it within seconds. So you add the resistor to drop the voltage going to the LED.
Thanks, I use a 470 ohm resistor correct? How do I know to use the 470. Is there a calculation for dropping the voltage.
Um.. i don't know it this'll be the easiest thats just one of them: http://metku.net/index.html?sect=view&n=1&path=mods/ledcalc/index_eng#parallel But, yeah just got with 470 ohm Its a bit to high (IMHO) but'll work just fine.
The resistor goes between the switch and the LED? Some of the tutorials i've seen have the LED attached directly to the switch with the resistor between the positive terminal and the led. I'm doing my first mod as well. So as long as the resistor is in there anywhere its fine? Been a long time since i've soldered anything as well. Getting that damn positive terminal into the middle of the connector took several tries hehe. I eventually got it. Burned the hell out of my finger, but I GOT IT! now just getting that damn rubber gasket back into the connector.
the "easiest", how I did it was positive term--> button->resistor->led-->neg &for atty button-->atty postive(middle)---> atty neg to batt neg. I'll try drawing,ugh... lol Or jacking a pic from somewhere ltr 2night and will post it up.
mad vapes has a great "how to"section on mods.made my 1st box mod last week.came out pretty descent.like the other person said if you put 3.7 volts on a led they"ll blow.they only need 1to2 volts max.to work imo
